In the examples on the previous page, the traveler on board the Space ship is not in a position to measure the time taken for the photon to move in both separate directions, but instead, if he is sitting at the " OD " position, he will be able to measure the time taken for the photon to complete the entire path from end, " OD ", to the opposite end and back again to " OD ". And so it does not matter which end of the space ship the " OD " and the traveler are positioned, the time measured for the photon to complete the round trip is always the same and still would be the same even if the space ship was traveling backwards. As we will see in Fig #13 down below, even if the space ship was moving sideways, if still traveling at 260,000 km per second, the time measured for the photon to complete the round trip, will still be the same. Hence, light is measured as being isotropic, therefore passing the Michelson and Morley tests, and so it is to be noted that the results of rotating the Michelson and Morley test apparatus to different test positions, is no different than rotating the Space ship such that it is moving either sideways, forwards, or backwards, and under all of these conditions, the results are the same. But these understandings of bi-directional measurements can throw people off track if only half the round trip is taken into account, or a half round trip is compared to a full round trip, such as in the following examples.
"gedanken" (thought) experiments to illustrate the consequences of his Special Theory of
Looking at the above experiment, what has occurred is that lightning has simultaneously struck the train at both ends. From the red mans point of view, the lightning seems to have occurred at the two opposite ends of the train at the same time. From the green mans point of view, the lightning seems to have struck the front of the train first, since he sees the lightning flash occur at the front of the train first, and then another from the back of the train moments later. Therefore logic says that one event can be seen twice. What am I talking about ?
In the above experiment, two simultaneous events seem to be both simultaneous and not simultaneous. To help clarify this point, I will reverse the experiment such that one event is all that is required. This time we will have only one bolt of lightning, and we will have mirrors at the opposite ends of the train. In this format, a single event would be seen TWICE if seen by looking at the mirrors. In the following example, we have a round trip light path compared to a less than complete round trip light path.
If you observed only the light represented by the yellow brackets, then the green man would have seen the light reflected from the mirror on the front of the train first, and then the light reflected off the mirror at the back end of the train secondly, but not see it until the train is much further down the track. Meaning that if the green man was using binoculars and was looking in the forward direction, he would see the image in the mirror of the red man light up like a light bulb as the lightning hits the ground in front of him, and if then turned around and looked at the mirror at the back end of the train, he would again see the red man light up like a light bulb moments later. From his point of view, the poor red man was struck by lightning Twice.
In the first Einstein train example, where there is no reflection, here the speed of the light coming from both ends of the train is seen as being identical speeds from the stationary observers point of view who is in the middle. In my example the results are the same, meaning that the speed of light is again seen as being identical speeds of light coming from both ends of the train, even after the light is reflected off these moving bodies, these moving mirrors. However, to add to the confusion, according to Einstein, Simultaneity is not an absolute concept and depends on the frame of reference, and so even though Einstein's example illustrates that two bolts of lightning strike the train at the opposite ends simultaneously, this is just an observation and may not actually be true. In my case the mirrors are in motion and this does not change the speed of the light that reflects off of these mirrors, and also in my case, it is only an observation that the light reflects off of both of these mirrors at the opposite ends of the train at the same time and so this too may not actually be true. So how is it that ALL of these different conditions of Simultaneity and Non-Simultaneity can both be, and also at the same time not be, and how can all of this occur in combination with the fact that reflection off a moving body does not effect the speed of light. This is explained in the next few paragraphs.
So, does all this make any sense to you? Does the fact that the mirrors in motion are not effecting the speed of the light make sense to you? Let us verify this. Imagine that in this case the single bolt of lightning strikes the train in the middle where the green man is positioned. As shown in the above diagram, if the flash of light at the origin " O " is located in the middle of the train, then after having bounced off the mirrors it will reach the destination " D " which of course is also located in the middle of the train, and this occurs even though in this case the train is traveling at 260,000 km per second. Even in the case in which the observer is not onboard the train, the speed of light is also not effected by the fact that the mirrors are on the move relative to him ? How can this be ? The answer to the question is in the following statement !
With that taken into account, then the above example should produce the same results. In this example we have two synchronized movie projectors positioned behind the viewers head, a pair of binoculars, along with six mirrors. By having the projectors along with the viewer and his binoculars being positioned in the middle, the timing is the same as in the previous example, and so the movie being watched by the viewers left eye will be synchronized with the movie being watched by his right eye. Therefore it does not matter whether the viewer and all that surrounds him, including the mirrors, are all moving together at 260,000 km per second, or at 10 km per hour, the results will be the same. But it is to be noted that each common set of images that are projected from the two synchronized movie projectors, will not actually reach the left and right end mirrors at the same time unless everything, other than the light, is at a stand still in space.
In the above example, the situation is similar to my train example. It does not matter what the Velocity is, it takes longer for the light to reach the left eye than it does to reach the right, due to the fact that the light path for the left eye is longer than the light path for the right eye. And so in this case, if the distance between the end mirrors was 300,000 km, then it would take 1.25 sec. for the light to reach the left eye, and 0.75 sec. to reach the right eye. End result, the movie viewer would think that the two movie projectors were half a second out of phase with each other. Yes, there is a specific velocity in which the common set of images that are projected from the two synchronized movie projectors will bounce off the two end mirrors at the same time, as in my train example, but still the timing required to then reach the viewer in the middle will still not be equal since he is in motion, therefore still creating the phase shift between the left and right images. In Einstein's example, just because it appears as though two bolts of lightning have struck the train at the opposite ends at the same time, it does not mean that this is the actual case unless earth was not on the move through space but instead earth was at a complete standstill in space.
And so I make my point. Just because two events may happen at the same time, it does not mean that it will appear this way to all viewers, or perhaps to any viewers at all. However, if you are at the position of a singular event as the event took place, this will cause what seems to be simultaneous events to take place at equal distances from you, such as the time when the light from the lightning reflects off the two mirrors which are positioned at equal distances from you, even though they may or may have not been actual simultaneous events. So it can get a little confusing.
According to Einstein's purely " RELATIVISTIC " view of reality, Simultaneity does not exist. This is NOT true ! One should be looking at the complete Holistic view and not just at the Relativistic point of view, and it must be understood that the Holistic point of view is greater than the sum of its parts, and therefore if one tries to explain it in relativistic terms, then you will end up with incomplete explanations.
Proudler used his own (lateral
thought) experiments to illustrate the consequences of his Absolute Theory of
Einstein's postulate: (a) the speed of light is constant ( The same in all inertial frames, independent of the motion of the source and the same in all directions. ) is both leading and misleading because it is not constant relative to all inertial frames, but when " Measured " it appears to be constant in all inertial frames, meaning it only " Appears " to be isotropic in all inertial frames. On the leading side it is correct to say that speed of light is constant across space within the universal frame of reference. To understand what is really happening, we must therefore continue to take the basic steps required to understand the complete outcome of changing ones direction of travel in Time-Space, meaning we must look at the situation from the Holistic point of view. Changing the direction of travel also changes ones perception of Time-Space itself, as we shall see shortly.
In the above example, the train is in a rush, and is clipping along at 260,000 km per second, and at this speed its spatial length has contracted from 75,000 km to 37,500 km. According to Einstein, it is in its own independent reference frame. A Clock is also positioned at each end of the train, and both are synchronized. Further on down the track, there are two more clocks, #3 & #4, which are also synchronized with each other, but in this case are ground based as is the train track. All clocks are being used as timers. Let us assume that from one end of the train to the other end, there are two narrow flex tubes that are hollow and have a mirror finish on the inside. The ends are capped, and inside of each tube, is a vacuum. These flex tubes will therefore function as optical fibers, but with there being a Vacuum inside, the speed of light will not be affected. Let us also assume that at the point further down the track where the track becomes a loop, that there are also two more flex tubes, each starting between clocks #3 & #4, with one completing the loop clockwise and ending at Clock #3, and the other completing the loop counter-clockwise and ending at Clock #4.
Under these conditions, if lightning strikes between clocks #3 & #4, then we will note the time readings at both clocks #3 & #4 to record this event. The light will then travel down both flex tubes that are laid down between the tracks. When the light completes the clockwise path, the time will be noted at Clock #4. When the light completes the counter clockwise path, the time will be noted at Clock #3. Both time periods measured, will be the same, for the distances from end to end of both the counter clockwise and clockwise flex tubes are Equal. ( See GREEN and YELLOW light paths on the above diagram. )
However, these equal time period measurements do not apply to the time period measurements taken on the Train, as the train circles the loop. In this situation it is to be noted that we are not arguing whether or not two events are synchronized, because we have only one lightning strike, and not two as in Einstein's Train Thought experiment. In my Train experiment, we will note the time readings at both clocks #1 & #2 to record this lightning strike event. Again, as in the previous example, light will travel down the flex tubes, both clockwise across one, and counter clockwise across the other , but in this case these flex tubes are attached to the train, and therefore are in motion with the Train. When the light completes the clockwise path, the time will be noted at Clock #2(Red). When the light completes the counter-clockwise path, the time will be noted at Clock #1(Blue). Both time periods measured, will NOT be the same, for the two distances that light must travel, are NOT Equal, due to the Train, and the destination clocks, moving further down the track. ( See RED and BLUE light paths on the above diagram. )
This is presently known as the SAGNAC Effect.
What we have here is a case in which the time taken for light to cross from one end of the train to the other, is not the same when in the opposite direction. This has been tested and confirmed by setting up a rotating test apparatus known as the SAGNAC INTERFEROMETER, which detects Change in interference patterns, and the position of the interference fringes is dependent on the Angular Velocity of the rotating SAGNAC INTERFEROMETER apparatus itself.
My previous pages, and Logic, say that this inequality must also apply if the train is moving in a straight line, even though Einstein's Theory of Special Relativity says not. If not, this means that as the train moves down the straight track, the time taken for light to travel from end to end of the Train, is to be equal in both directions, then, as it proceeds to do the loop, the time taken for light to travel from end to end of the Train, is NOT to be equal in both directions , then, after it completes the loop and returns to the straight track, the time taken for light to travel from end to end of the Train, is to be equal in both directions once again. ??? In other words, if just after the lighting struck, we popped up mirrors at the ends of the train such that most of the light could then be reflected back and forth from end to end as the train proceeded onward, then this implies that the behavior of the light will somehow change after the train has left the loop, such that from here onwards the light is to magically travel from either end to the other in equal time.
In this Train example, we have also synchronized the clocks once again when the lightning strikes between the Engine and the Caboose, and this effect of synchronizing will be carried with each clock after leaving the loop and returning to the straight track. Logic says that when the train has returned to the straight track, light will still take much longer to travel from end to end of the train when the light is moving in the same direction as the train itself is moving, in comparison to the time taken for light to complete the trip in the opposite direction. This is true, however, those onboard the train will disagree. Is this due to the " Magic " of Relativity ? NO. As we will see shortly, it is due to the specific direction of travel across Time-Space.
To make motion across space possible, all particles must simulate having an existence at more than just one place, just as in the case of the hypothetical flexible object mentioned on page one of the introduction. I say simulate, becauseimpossible is impossible, and so it can not truly be present at more than one place.
So what is the SECRET ?
To make motion across space possible, all particles must have a spin property . With a spin axis tilting across both time and space, this allows the particle to simulate its existence being at more than just one place at one time, and more than one time at one place. However, in actual fact, it rotates back and forth across Time as well as rotating across Space, all while it is in the process of moving. Bingo, this makes the birth of motion possible. Therefore, if the particles are now in motion through space at 260,000 km per second, not only have we changed the direction of travel of the particles, but we have also rotated the spin axis of the particles even further, such that less rotation is extended across space, and more of the rotation is now extended across the time dimension.
FIG. # 12
But this contraction across the Spatial Plane, only occurs in the direction of travel. Therefore, as shown in the next diagram FIG. #13, even if our Space Ship was traveling sideways at 260,000 km per second, the space ship length would remain as 75,000 km, but the Time periods measured on the travelers clock will still be affected and can be calculated using the equation on the right of FIG. #12 above.
In FIG. # 13 below, the actual path across space, between the Origin and the Destination or (a * 2), is (150,000 km * 2), meaning 300,000 km. However, with the traveler being totally unaware of this side traveling at 260,000 km per second, the additional 150,000 km distance across space, is not seen by the observer in motion, hence the distance the light moves from end to end of the space ship, is still 75,000 km * 2 ( 150,000 km ) , and the time period ( t2 - t1 ) measured on the clock onboard the space ship indicates only 0.5 of a second rather than 1 second ( t2o - t1o ). 150,000 km in 0.5 sec = 300,000 km per second, and so the measurement of the speed of light is still the same standard 300,000 km per second even under these side motion circumstances. Therefore once again the results are in agreement with that of the Michelson and Morley tests taken in 1887, and others alike taken more recently.
FIG. # 13
Based on the examples of both Forward and Side travel, it is shown that both result in the same Time - Space distance covered by each photon moving from the Origin and the Destination ( 424,264 (km) ). In both cases, the observer onboard the Space Ship sees it as a round trip across a 75,000 km distance, completed in 0.5 of a second.
In the above example, we have a Photon traveling from the bottom of the Tower to the top, and back down to the bottom of the Tower. If the Tower height ( Ho ) is 75,000 km tall when at rest, then it would take the Photon 1/2 of a second to complete the round trip of 150,000 km, since the speed of light is 300,000 km per second. If however, the Tower was on a cart, and the cart was traveling at 260,000 km per second, the height of the Tower would remain as 75,000 km ( H ), L1 and L2 would each be 130,000 km, but the light paths #1 ( CP1 ) and #2 ( CP2 ) would now each be 150,000 km, therefore bringing the total to 300,000 km. The end result is that in one second ( to ) from the stationary observers point of view, the light will have traveled a total of 300,000 km, and so once again, the measured speed of light is 300,000 km per second. If on the other hand one stays with the Tower while it is on the move, the total time period observed is 1/2 of a second, ( t ) , and it appears as though the photon has traveled up 75,000 km and down 75,000 km (150,000 km total) in that 1/2 a second time period, just the same as it was seen to be when the Tower was at rest. Therefore, to both a stationary observer, and the observer who is on the move with the Tower, the speed of light is still measured to be the same 300,000 km per second.
In this next example above, I show the Tower on its side ( Picture 2x larger ). While at rest on its side, it still requires 1/2 of a second for the Photon to complete one round trip. If the Tower is also on the moving cart, and moving at a velocity of 260,000 km per second, the results are the same as in the Space Ship example on the previous page, and the length of the Tower on its side will contract from 75,000 km ( Ho ), to 37,500 km ( H ). In this case, both the light path #1 ( CP1 ) and L1 are 280,000 km long, and both the return path ( CP2 ) and L2 are 20,000 km long. And so, the total light path is 280,000 km + 20,000 km = 300,000 km, and the total path is completed in 1 second ( to ) . Here again the stationary observer measures the speed of light as 300,000 km per second. If on the other hand one stays with the Tower while it is on the move, the total time period observed is 1/2 of a second, ( t ) , and, due to being unaware of the contraction of the Tower, it appears as though the photon has traveled to the right 75,000 km and to the left 75,000 km (150,000 km total) in that 1/2 a second time period, just the same as it was seen to be when the Tower was at rest. Therefore, to both a stationary observer, and the observer who is on the move with the Tower, the speed of light is still measured to be the same 300,000 km per second.
It is to be noted that in the above ( to ) equation, c - v and c + v do not imply that the speed of light has been altered, but we are simply taking the movement of the Tower into account relative to the speed of that light. As stated previously, when light reflects off of a moving body, it does not change the velocity of that light, and in the next paragraph, it is also made clear that a moving body that emits light does not change the velocity of that light, but that the light remains at the velocity of 300,000 km per second relative to the universal background.
As previously stated, there is the consistency of the Holistic spin diameter. However, the Holistic spin axis changes under situations such as when a mass particle has a greater percentage of its constant motion moving through Space and less through Time than previously. In figure #8 of Part Two of Four Dimensional Particles, the Meson decays while at rest in space and in motion in time. If on the other hand the Meson was in motion through space at the time of the decay, one would expect the motion of the photons to no longer be 300,000 km per second across Space. But this is only the conclusion one draws if one overlooks the change of the Holistic axis angle of the Meson that has occurred as the result of, and in combination with, its new motion across Space and new less motion across Time. For one Axis of the two Axis of the Meson, the Spatial angular motion is increased in the reverse direction as the result of the overall shift in the Meson's axis across Time-Space, and hence for the other Photon, the Spatial angular motion in the forward direction has decreased. Therefore, one Photon that is released at the point of decay, is heading in the opposite direction than the Meson was traveling across Space, but at ( 300,000 km per sec. + v ) speed relative to the velocity of the Meson. This cancels out any effect the Meson's velocity has in attempting to change the universal 300,000 km per second velocity of Photons across Space. The other Photon that is released at the point of decay, is heading in the same direction as the Meson was traveling across Space, but at a ( 300,000 km per sec. - v ) speed. This again cancels out any effect the Mesons velocity has in attempting to change the universal 300,000 km per second velocity of Photons across Space.
This affect applies to all matter while in motion across Space, as it releases a Photon or Photons.
In the diagram above, the arrows indicate both the percentage of the Holistic spin which is in motion across Space, and the percentage of the Holistic spin which is in motion across Time. When at rest in space, there is balance between Photon #1 and Photon #2 in determining how fast the Photons will travel across Space once released. In the above diagram on the right, the Meson is in motion across Space at a high velocity. In this case, the axis have rotated as expected due to the rotation in the direction of travel in Time-Space. The Holistic spin of Photon #1 has rotated such that the spatial angular spin has increased. The Holistic spin of Photon #2 has rotated such that the spatial angular spin has decreased. The end result of this axis rotation, is that both Photons once released will be of equal (c) velocity across space, by having canceled out any effects given by the velocity of the Meson itself. Therefore we can say that there does exist the case of ( c + v ) and ( c - v ) velocities which in turn set and maintain the universal velocity of light to 300,000 km per second.
argument that many Physicists make to support their version of Einstein's claims, which is
that light travels in all directions at the same speed within any inertial frame, is based
upon using a moving light source as part of the proof. As an example, they say
This of course is a clear cut mistake due to a constant dedication to assumption, in this case being backward assumption. As I said, light is always emitted from a moving body at the speed of light in any direction relative to the Universal background medium, but it is NOT emitted at the speed of light relative to the moving body itself, nor is it moving at the velocity of the speed of light in all directions relative to a moving frame of reference . The ( c + v ) and ( c - v ) velocities truly DO exist, but in the exact opposite manner than that spoken of in the above quotation.
And so from
this we can conclude that the above Michelson-Morley experiment in a way proves that the
speed of light is isotropic in the universal frame of reference, but it does not in anyway
imply that light actually is isotropic relative to any moving frame of reference, but that
light may be measured to be isotropic due to the specific properties of a moving frame of
reference that differ from one moving frame of reference to another. We will get into these
It is to be clearly noted that there are two constant motions.
Taking into account the consistent motion of all objects, the proper reference would be seen from the Universal point of view.
chapter 3 of Space and Time in Classical Mechanics, made the following statement.
" It is not clear what is to be understood here by "position" and "space." I stand at the window of a railway carriage which is traveling uniformly, and drop a stone on the embankment, without throwing it. Then, disregarding the influence of the air resistance, I see the stone descend in a straight line. A pedestrian who observes the misdeed from the footpath notices that the stone falls to earth in a parabolic curve. I now ask: Do the "positions" traversed by the stone lie "in reality" on a straight line or on a parabola? Moreover, what is meant here by motion "in space" ? From the considerations of the previous section the answer is self-evident. In the first place we entirely shun the vague word "space," of which, we must honestly acknowledge, we cannot form the slightest conception, and we replace it by "motion relative to a practically rigid body of reference." The positions relative to the body of reference (railway carriage or embankment) have already been defined in detail in the preceding section. If instead of " body of reference " we insert " system of co-ordinates," which is a useful idea for mathematical description, we are in a position to say : The stone traverses a straight line relative to a system of co-ordinates rigidly attached to the carriage, but relative to a system of co-ordinates rigidly attached to the ground (embankment) it describes a parabola. With the aid of this example it is clearly seen that there is no such thing as an independently existing trajectory, but only a trajectory relative to a particular body of reference. "
Here we have two different points of view. One sees a straight path, and the other sees a parabolic curve. But in truth, neither is correct. In truth the stone has changed its direction of travel within Time-Space. As I have said, the proper reference would be seen only from the Universal point of view.
This also brings an important point to the surface. If one releases a stone that is suspended above the Earth, it begins to change its direction of travel in Time-Space such that its travel across Space has increased, and its travel across the dimension of Time has decreased instead. This then implies that when positioned deep within a gravitational field, a clock will run slower than a clock that is much further from the source of that gravitational field. This has been confirmed to be true, just as logic dictates it should be true.
For instance, if clock (A) is placed at sea level at the equator, it will run at the same speed as clock (B) that is also placed at sea level but is located closer to the north or south pole. This will occur even though clock (A) at the equator is moving across space at a greater velocity than clock (B). But one has to take into account the fact that Earth has an elliptical shape as the result of its rotation, and so clock (A) is further from the center of the gravitational force than is clock (B). Therefore, at the location of clock (A), where the gravitational effect upon the clock is less, the effect upon the clock due to motion across Space, is greater. For clock (B) it is the opposite. The end result is that the total effects upon both clocks (A) and (B) become equal. Without the effect of gravitation upon the clocks, this balance would not occur.
Reviewing the above drawing on the right, you will recall that the light path #1 ( CP1 ) is 280,000 km ( 279,710.171 km ) long, and that light path #2 ( CP2 ) is 20,000 km ( 20,082.287 km ) in length. Light traveling at 300,000 km per second ( 299,792.458 km per sec. ), crosses the light path #1 ( CP1 ) in 0.9330127 of a second, and the light crosses light path #2 ( CP2 ) in 0.0669873 of a second. Obviously the Time taken for the light to complete the path in one direction is not the same as it is to complete the path when the light is heading in the opposite direction. Yet Einstein says that the light should move in either direction from end to end in the same Time period. This is not entirely true !
Instead, what has occurred is that once the Tower on the cart is accelerated to the speed of 260,000 km per second ( 259,627.8845 km per sec. ) relative to being at rest in space, the Tower now also extends across Time. This then takes effect upon the outcome of measuring the speed of light, if one is measuring the speed of the light while onboard the Tower, as the Tower is on the move.
On the diagram above on the left, we see again the diagram which has so far provided us with the Lorentz - Fitzgerald Contraction equation, and the Time Dilation equation. Once again it will inform us of additional reliable information.
Here in the diagram, the Object Unit's motion is pointing in the direction across Time-Space such that it's spatial velocity is 260,000 km per second ( 259,627.8845 km per sec. ), just as is the velocity of the Tower. At this velocity, the Object Unit is rotated in Time-Space, and thus results in the Object Unit extending across 0.8660254 of a Time Unit. At the rear end of the Object Unit, there is an offset of ( + 0.4330127 ), and an offset of ( - 0.4330127 ) at the front end. With ( c ) being the constant motion measure of all mass particles within Time-Space, this provides us with a standard reference measure of Time, Space, and Objects. Since the ( c ) constant equals 299,792.458 km per second, a one second Time Unit is equivalent in length to a 300,000 km ( 299,792.458 km ) Space Unit length, and is equivalent to a 300,000 km ( 299,792.458 km ) Object Unit length, and all units on the diagram, Space Unit, Time Unit, and Object Unit, are all set to the equal measure of ( c ), and thus become our standard reference units.
With the Object Unit being the Tower, the Object Unit length is 75,000 km ( 74,948.1145 km ) when at rest in space, rather than being the same as the 300,000 km ( 299,792.458 km ) length of the reference Object Unit shown in the diagram. This difference must therefore be taken into account by simply addition division into the equation. The 0.8660254 of a Time Unit, is determined by v / c.
Therefore, the extension of the Tower across time while the Tower is in motion across space at the velocity of 260,000 km per second ( 259,627.8845 km per sec. ), equals ( 74,948.1145 km / 299,792.458 km * v / c = 0.21650635 ). The time offsets are therefore ( - (0.21650635 / 2 = 0.108253175) ) at the front of the Tower, and ( + (0.21650635 / 2 = 0.108253175) ) at the rear of the Tower. The total of these time offsets is 0.21650635 sec., and so if clocks were positioned at both ends of the Tower, then the clock at the back end of the Tower will be ahead of the clock at the front by 0.21650635 of a second.
Note : Since
the " 299,792.458 km " Object Unit reference length is also the distance
light travels in 1 second ( c ),
While the Tower is being accelerated to 259,627.8845 km per sec., the Tower is being rotated across Time-Space, and each clock onboard is slowing down. Once the Tower on the cart is traveling at the velocity of 259,627.8845 km per sec. , t' = t * 0.5 , therefore due to the clocks now ticking at half speed, the measuring of the ( CP1 ) 0.9330127 sec. light path time period becomes ( 0.9330127 * 0.5 = 0.46650635 sec. = t'1 ) and the measuring of the ( CP2 ) 0.0669873 sec. light path time period becomes ( 0.0669873 * 0.5 = 0.03349365 sec. = t'2 ).
With all this taken into account, and if it is agreed by those monitoring each clock at each end of the Tower that the light will be released at 0.00 time, the person at the front of the Tower where the light is received will be unaware that the other persons clock is ahead of his by ( + 0.21650635 sec. )and therefore will think that the light was released at the 0.00 time relative to only his own clock. By the time his clock registers 0.00, the light will already have traveled for 0.21650635 of a second. This will therefore subtract 0.21650635 sec. from the measuring of the 0.46650635 sec. time period. ( 0.46650635 - 0.21650635 = 0.25 sec. ). Since v = x / t , 74,948.1145 km / .25sec. = 299,792.458 km per second. Therefore it appears to the observer on the Tower, who still measures his Tower to be 74,948.1145 km in length since his measurement instruments have also contracted in spatial length, as though the light has still traveled from one end of the Tower to the other at the expected speed of light.
( t'1 - v / c 2 * x = 0.25 sec. = t'1 as measured by the observer )
If instead the light was released from the front end of the Tower at 0.00, we would simply add the 0.21650635 sec. time offset to the 0.03349365 sec. time period, since the clock at the rear end of the Tower is already ahead by 0.21650635 of a second at the very same time that the light is released from the front end. ( 0.03349365 + 0.21650635 = 0.25 sec. ). Since v = x / t, 74,948.1145 km / .25sec. = 299,792.458 km per second. Therefore, in this case as well, it also would appear as though the light has traveled from one end of the Tower to the other at the expected speed of light.
( t'2 + v / c 2 * x = 0.25 sec. = t'2 as measured by the observer )
You may think that it does not make sense for one end of the Tower to be ahead in time and the other to be behind, but you have to understand that the " Present Time " is still being shared by all. What this means is just as I have stated before, that all objects travel with the (c) motion in Time-Space. Therefore, at any time, all objects are at an equal distance in Time-Space from where they were positioned just moments beforehand in that Time-Space. This is what they all have in common. This is how they are all grouped together. This is what the " Present Time " actually is.
And so, when reviewing the above Train and loop example, it becomes clear that the time measured for light to travel from one end of the train to the other end while on the loop, would not be the same in both directions, but once off of the loop and back onto the straight track again, the time measured for the light to travel in either direction from end to end of the train would be the same. As is the Tower, the Train in motion is also extending across Time-Space, and so the length of that Train determines how far apart the clocks are displaced from each other across Time. When the train is on the loop and the engine meets the caboose, the clocks are no longer extended across Time-Space with great distance between the clocks, and therefore the clocks are no longer being displaced across Time from each other, but are now truly synchronized.
With the clocks being synchronized, and the speed of light being a universal constant, the effects of the train following a circular path due to being on the loop, are detectable if the time taken for the light to travel from one end of the Train to the other end, is compared to the time taken for the same to occur but in the opposite direction. After returning to the straight track, the significant distance between the clocks is restored, and so Einstein's " Relativity " is restored, and not by magic, but by reason that I have now described in simple words. If you do the math, you will see that even if light was released from a light source located at the center of the Train in the above diagram, that due to the Clock Time offsets, the time registered at each clock at the instant the light reaches each clock, will be an identical reading. Each clock will give the exact same reading. If one clock says that the light reached that clock at 12:00AM, then so will the other at the other end of the train !
Now that it
has been explained in simple terms that can be easily understood, let's introduce equations
into the picture.
Looking at the diagram above on the right, if the event taking place is light traveling from one end of the Tower on its side to the opposite end, and the Tower velocity ( v ) is 260,000 km per second ( 259,627.8845 km per sec. ), then the ( x' ) in the moving ( K' ) frame of reference will equal the length of the Tower as measured by the observer in this ( K' ) frame while using his measurement instruments that move with him in the ( K' ) frame. ( x'1 ) is the distance from ( O' ) to the end of the Tower where the light is emitted, and ( x'2 ) is the distance from ( O' ) to the other end of the Tower where the light is received. Onboard the cart it is still believed that the Tower on its side is still at its original 75,000 km in length since there is no way to detect any contraction in its length while being present within the moving ( K' ) frame of reference. This is due to his measurement instruments also having contracted in length.
From the ( K ) stationary frame of reference we can calculate the perceived length of the Tower as seen in the moving ( K' ) frame. The simple equation I have constructed to do so, is shown on the right. At the time that the event begins, the two origins, ( O ) and ( O' ), are located at the same position. In our Tower example, we are onboard the Tower in the ( K' ) frame, and we are therefore not displaced from the event by being positioned elsewhere within the ( K' ) frame. Therefore ( x 1 and x'1 ) are set as 0.0 when the event begins as the light is released at the rear end of the Tower. The ( v ) velocity of the Tower in motion across the x axis is 259,627.8845 km per second.
With the time period for the light to travel from end to end of the Tower being 0.9330127 of a second if the light is traveling in the same direction as the Tower itself, ( x 2 ) will be equal to ( 259,627.8845 km * 0.9330127 = 242,236.114 km ) plus the 37,474.057 km contracted length of the Tower. The total is therefore 279,710.171 km. ( x = x 2 - x 1 ) = 279,710.171 km - 0.0 = 279,710.171 km. Therefore x - vt = 279,710.171 km - ( 259,627.8845 km * 0.9330127 ) = 37,474.057 km. The remaining portion of the equation gives us the magnitude of contraction, which in this case equals 0.5, therefore x' = 37,474.057 km / 0.5 = 74,948.1145 km. The actual spatial length of ( x' ) is of course the 37,474.057 km, but we are calculating the length of ( x' ) as seen in the eye of the observer in the moving ( K' ) frame of reference, and so we therefore include the length of the Tower with the contraction reversed since the observer is unaware of the contraction which has occurred as the result of climbing to the velocity of 259,627.8845 km per second.
To create an equation such that we in the stationary ( K ) frame of reference can know what time period is measured for the event to occur as seen in the ( K' ) frame of reference , we must basically reverse the equations that we have used so far. When observed from the ( K ) frame of reference, the light had crossed the light path #1 ( CP1 ) which is 280,000 km ( 279,710.171 km ) long, in 0.9330127 of a second. From the moving ( K' ) frame of reference it appeared as though the light had completed the path in 0.25 of a second, and that the path itself was the 75,000 km ( 74,948.1145 km ) length of the Tower. Using the previous equations, we include the calculation of how far the " Object " extends across time, and we use the equation which had determined the contraction of the ( K ) time period as it is experienced in the moving ( K' ) frame of reference.
( x =
74,948.1145 km , v = 259,627.8845 km per sec. )
The reversal of the equation produces the following.
( x =
279,710.171 km , v = 259,627.8845 km per sec. )
Hence the equation..
So far I have
used extremely simple logic and analysis of motion, but despite doing so, it appears as
though I have come up with a set of equations that are known as the Lorentz Transformation
equations. What a coincidence. Yet despite this, my facts do not agree with the current
One point still to be made is the fact that if the direction of the event taking place within the ( K' ) frame, is in the opposite direction to the direction that the ( K' ) frame is heading relative to the stationary ( K ) frame, then the first negative sign in the above equation must be changed to a positive sign, just as I am sure you remember from the previous examples. But at least it is clear as to why such a reversal is required since all the facts are exposed.
( x =
20,082.287 km , v = 259,627.8845 km per sec. )
So there they are, the Lorentz Transformation equations. Amazing isn't it !
That which I have revealed can be useful since it is composed of TRUTH, but unfortunately that is not allowed in today's conformal society. The worship and obedience of a Conformal Belief System is all that is currently approved of. TRUTH has no place in this world.
The motion of light is constant across Time-Space. The motion of all objects is also constant across Time-Space. Therefore there is a foundation which creates all relativistic conditions. If a moving object releases a Photon, the Photon will still travel at the (c) velocity relative to the universe itself. If one approaches the Photon, or is moving away from the Photon, the measuring instruments themselves are altered by extending across Time, shortening in spatial length, and the measuring instrument clocks involved are ticking at a slower speed, all such that the measuring instruments themselves will still measure the universal speed of the photon to still be 299,792.458 km per second even though the measurement platform is in motion one way or another relative to the Photon. As the result of this creation of relative conditions, there is no way to determine if one is truly at rest in space or not.
back to the Train again. At this time, we are aware that if onboard the Train, it still
appears as though light takes 0.25 of a second to go in either direction from end to end of
the Train even if the Train's velocity is 259,627.8845 km per second. At this velocity the
clocks readings are offset from each other by 0.21650635 of a second. If the Train is then
brought to a halt on the tracks, once again the clocks are synchronized now that the train
no longer extends across the dimension of Time. Therefore the clocks can be set to meet the
at rest synchronized condition, even while moving at a high velocity, and this is done by
sending light from one clock to the other while also knowing the standard 74,948.1145 km
length of the Train.
The next step is to determine how far the bullet had traveled as seen from the track side in the ( ) time period. This is determined by ( ) plus the length of the Train, not forgetting that the Train is seen in its spatial contracted length from the track side point of view. The total length ( ) is therefore determined by the following equation.
Now that we have the time period and the distance determined, the next step is ( / ) to determine the total of the addition of the two velocities.
The math is out of the way, so let's see if this is all making sense. In the above example, ( ) turns out to be 1.0103629712 seconds. Onboard the Train however, clocks are running at half speed, and so this time period becomes 0.50518149 of a second. Now if you recall the time offset between the clocks, the clock at the front of the train is behind the clock at the rear by 0.21650635 of a second, and so this must be subtracted from the 0.50518149 sec, time period. ( 0.50518149 sec. - 0.21650635 sec. = 0.28867514 sec. ). Onboard the Train it appears as though the bullet is moving from end to end of the Train at a velocity of 259,627.88445 km per second, and from the passengers point of view, the train length is still 74,948.1145 km long. Therefore the time required to complete this trip is determined by ( 74,948.1145 km / 259,627.88445 = 0.28867514 sec. ), and so it is a match. Everything is in agreement even though those onboard the train, as it speeds down the tracks at 259,627.88445 km per second, think that the bullet is moving at 259,627.88445 km per second in addition to the Train's velocity. Meanwhile, those at the track side would measure the bullets velocity to be 296,717.5822 km per second relative to the statioianry tracks. From the track side point of view, the bullet is only moving 37,089.698 km per second faster than the Train.
Now since this velocity addition occurs in this manner, there is no clear cut way to determine if you are truly at rest in Space. All that can be done is determine whether or not you are moving faster across Space than another, or slower. If your clocks are ticking at a slower rate in comparison to those whom you are passing by, or are passing by you, then you are in motion across space at a higher velocity. If it is the opposite, then you are moving across Space at a slower velocity.
We can keep adding a velocity after velocity, we can have moving objects releasing other moving objects, etc., and all seems well, yet at the same time we are unaware that each addition does not produce the expected results, but instead the total velocity is always kept to less than the spatial speed of light, 299,792.458 km per second, while at the same time our perception of each additional velocity is being altered the precise amount required to compensate for such a limitation. This then gives some people the impression that Relativity is the cause of all of this, and that Relativity is simply an independent function that has no foundation or cause !
So far by using a simple step by step analysis of motion, I have also created the Lorentz Fitzgerald contraction equation, the Time Dilation equation, the Lorentz Transformation equations, and now the velocity addition equation. The analysis has provided the explanation for the creation of that presently labeled as " Relativity ", yet of course the explanation is immediately rejected because it has a foundation. At this time, as I have said, complete explanations are not welcome. Read and understand this entire web site, and you will understand why TRUTH is rejected, and for what reason. But, let's carry on before the truth disappears in puff of smoke.
Wow, what can I say ?
Determining the precise position of a particle in motion is also limited because of its movement back and forth across time. However, it is also a consistent limitation since any change is compensated for, meaning, if a particle reduces in spatial size it also has increased the width of the extension across time. All this because Holistically, its spin diameter has not changed. To this day, by not thinking four dimensionally, Physicists have only a mathematical equation that predicts these Uncertainties, such as the position of an object, but it does not include the understanding that particles have a four dimensional spin which is the cause of these Uncertainties.
This Uncertainty will also therefore apply to Energy and Time readings !
- is the uncertainty or imprecision (standard
deviation) of the position measurement.